Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
F_net = 1.125 10⁻⁶ N
positive direction of the x axis
Explanation:
The electric force is given by Coulomb's law
F =[tex]k \frac{q_1q_2}{r_{12}^2}[/tex]
also used charge of equal sign repel each other.
We appease this information to our problems
the charge q₁ is positive and the charge q₃ is positive for which the force is repulsive; ; a charge q₂ is negative so the force is attractive.
If we apply that the forces are vectors
F_net = - F₁₃ + F₂₃
F_net = [tex]-k \frac{q_1q_3}{r_{13}^2} + k \frac{q_2q_3}{r_{23}^2}[/tex]
F_net = k q₃ ( [tex]- \frac{q_1}{r_{13}^2} + \frac{q_2}{r_{23}^2}[/tex] )
let's look for the distances
r₁₃ = 2-0 = 2 cm = 2 10⁻² m
r₂₃ = 4-0 = 4 cm = 4 10⁻² m
let's substitute
F_net = 9 10⁹ 5 10⁻⁹ ( [tex]- \frac{1 \ 10^{-9}}{2 \ 10^{-2}} + \frac{3 \ 10^{-9}}{4 \ 10^{-2}}[/tex])
F_net = 45 (- 0.5 10⁻⁷ + 0.75 10⁻⁷)
F_net = 1.125 10⁻⁶ N
the positive sign indicates that the outside has a positive direction of the x axis, that is, it is to the right
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
