josephdeane07
Answered

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HELP URGENT BRAINLIEST

HELP URGENT BRAINLIEST class=

Sagot :

Given:

LMN is an equilateral triangle.

LM = LN = MN = 12 cm

To find:

The height of the triangle h.

Solution:

In a right angle triangle,

[tex]\sin \theta=\dfrac{Opposite}{Hypotenuse}[/tex]

[tex]\sin (60^\circ)=\dfrac{h}{12}[/tex]

[tex]\dfrac{\sqrt{3}}{2}=\dfrac{h}{12}[/tex]

Multiply both sides by 12.

[tex]\dfrac{\sqrt{3}}{2}\times 12=\dfrac{h}{12}\times 12[/tex]

[tex]6\sqrt{3}=h[/tex]

Therefore, the height of the triangle is [tex]6\sqrt{3}[/tex] cm.

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