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How many moles would you need to have 7.85 x 10^22 molecules of ammonia (NH3).

Sagot :

Space

Answer:

0.130 moles NH₃

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 7.85 × 10²² molecules NH₃

[Solve] moles NH₃

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

  1. [DA] Set up:                                                                                                      [tex]\displaystyle 7.85 \cdot 10^{22} \ molecules \ NH_3(\frac{1 \ mol \ NH_3}{6.022 \cdot 10^{23} \ molecules \ NH_3})[/tex]
  2. [DA] Multiply/Divide [Cancel out units]:                                                         [tex]\displaystyle 0.130355 \ moles \ NH_3[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.130355 moles NH₃ ≈ 0.130 moles NH₃

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