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What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (-2, 4)?
O y=-5/2x-1
O y= -5/2x+ 5
O y=2/5x-1
O y=2/5x+5


Sagot :

Answer:

[tex]y = -\frac{5}{2}x-1[/tex]

Step-by-step explanation:

5x + 2y = 12

2y = -5x + 12

[tex]y = -\frac{5}{2}x +6[/tex]

Parallel lines have the same slope so the -5/2 remains. Just remove the b value (6) and plug in (-2,4) to the x and y spots.

[tex](4) = -\frac{5}{2}(-2) + b[/tex]

4 = 5 + b

b = -1

The new equation is [tex]y = -\frac{5}{2}x-1[/tex]