Undertaler
Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

what is the common ratio of a geometric progression were the first term is 3 and the 4th term is 648​

Sagot :

MrRoyal

Answer:

[tex]r = 6[/tex]

Step-by-step explanation:

Given

[tex]a = 3[/tex] --- First, term

[tex]T_4 = 648[/tex] --- Fourth term

Required: Determine the common ratio

The nth term of a GP is

[tex]T_n = ar^{n-1[/tex]

Substitute 4 for n

[tex]T_4 = ar^{4-1[/tex]

[tex]T_4 = ar^{3[/tex]

Substitute 648 and 3 for T4 and 3 respectively.

[tex]648 = 3 * r^{3[/tex]

[tex]r^3 = 216[/tex]

Take cube roots of both sides

[tex]r =\sqrt[3]{216}[/tex]

[tex]r = 6[/tex]

The common ratio is 6

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.