Answer:
2.67 M
Explanation:
Molarity, which is the molar concentration of a substance, can be calculated using the formula;
M = n/V
Where;
M = molarity (M)
n = number of moles (mol)
V = volume (Litres)
Based on the provided information in this question, mass of lithium sulfate (Li2SO4) = 734g, volume = 2.5L
Using mole = mass/molar mass
Molar mass of Li2SO4 = 7(2) + 32 + 16(4)
= 14 + 32 + 64
= 110g/mol
Mole = 734/110
Mole (n) = 6.67moles
Molarity = n/V
Molarity = 6.67/2.5
Molarity = 2.668
Molarity of Li2SO4 in the solution is 2.67 M
Answer:
The molarity of the solution is 2.672[tex]\frac{moles}{liter}[/tex]
Explanation:
Molarity (M) is a way of expressing the concentration of solutions. It is defined as the number of moles of solute per volume of solution. The Molarity of a solution is determined by the following expression:
[tex]Molarity=\frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
Being the molar mass of Li₂SO₄ 109.94 g/mol, then you can apply the following rule of three: if 109.94 grams are present in 1 mole, 734 grams will be present in how many moles?
[tex]amount of moles=\frac{734 grams*1 mole}{109.94 grams}[/tex]
amount of moles= 6.68 moles
Then:
Replacing in the definition of molarity:
[tex]Molarity=\frac{6.68 moles}{2.5 L}[/tex]
and solving you get:
Molarity= 2.672[tex]\frac{moles}{liter}[/tex]
The molarity of the solution is 2.672[tex]\frac{moles}{liter}[/tex]
