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Kim and Jay leave at the same time to travel 25 miles to the beach. Kim drives 9 miles in 12 minutes. Jay drives 10 miles in 15 minutes. If they both continue at the same rate, who will arrive at the beach first?

Sagot :

ALX2020
I'm supposing that Kim and Jay live in the same places!

We'll turn 9 in 12 minutes to 3/4 and 10 in fifteen minutes into 2/3! 
3/4 is larger.
Kim will get to the beach first!

I hope this helps!
-Alex

Answer:

The average speed of Kim is greater than the average speed of Jay, therefore Kim will arrive at the beach first.

Step-by-step explanation:

It is given that Kim drives 9 miles in 12 minutes. So, the average speed of Kim is

[tex]S_1=\frac{9}{12}=0.75[/tex]

Therefore the average speed of Kim is 0.75 miles per minutes.

Jay drives 10 miles in 15 minutes. So, the average speed of Kim is

[tex]S_2=\frac{10}{15}=0.6667[/tex]

Therefore the average speed of Jay is 0.67 miles per minutes.

It is given that Kim and Jay leave at the same time to travel 25 miles to the beach.

Since average speed of Kim is greater than the average speed of Jay, therefore Kim will arrive at the beach first.

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