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A little boy pulls a spring with force constant k out a distance s and in so doing, does an amount of work W. By comparison, how much work would he do to pull the spring out a distance

Sagot :

Answer:

The answer is "[tex]w'= \frac{w}{4}[/tex]"

Explanation:

According to the work-energy theorem:

work = changes in the potential energy

[tex]w= \frac{1}{2} K S^2-0\\\\w= \frac{1}{2} K S^2. . . . . . . . . . . (1) \\\\w'= \frac{1}{2} K \frac{S^2}{2} -0\\\\w'= \frac{1}{2} K (\frac{S}{2})^2\\\\ w'= \frac{1}{2} K \frac{S^2}{4} . . . . . . . . . . . (2) \\\\[/tex]

by putting the w value in equation 2. so, the value is:

[tex]\boxed{w'= \frac{w}{4}}[/tex]

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