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You spin a spinner numbered from 1 to 8 twice​. Find the probability of getting a 1 on the first spin and a 2 on the second spin.

Sagot :

MrRoyal

Answer:

[tex]Probability = \frac{1}{64}[/tex]

Step-by-step explanation:

The sample space of the spinner is:

[tex]Sample\ Space = \{1,2,3,4,5,6,7,8\}[/tex]

So:

[tex]n(S)= 8[/tex]

All of which have the same probability.

Required

Determine the probability of 1, then 2 when spin twice

The probability of the first being 1 is:

[tex]P(1)= n(1)/n(S)[/tex]

[tex]P(1)= 1/8[/tex]

The probability of the second being 2 is:

[tex]P(2)= n(2)/n(S)[/tex]

[tex]P(2)= 1/8[/tex]

So, the required probability is:

[tex]Probability = P(1) * P(2)[/tex]

[tex]Probability =1/8* 1/8[/tex]

[tex]Probability = \frac{1}{64}[/tex]

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