Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Use the information given to find a convenient dass width. Then list the class boundaries that can be used to create a relative frequency histogram. (Round your class with up to the nearest multiple of 5. Use the minimum value as the smallest class boundary. Enter your class boundaries as a comma separated list.)
8 classes for 75 measurements; minimum value-20; maximum value = 175
class width
class boundaries

Sagot :

nuhulawal20

Answer:

a)

Class width = 19.375

b)

Class Boundaries are;

19.5 - 39.5, 39.5 - 59.5, 59.5 - 79.5, 79.5 - 99.5, 99.5 - 119.5, 119.5 - 139.5, 139.5 - 159.5, 159.5 - 179.5.

Step-by-step explanation:

Given the data in the question;

Class width = Range / Number of classes

Range = maximum - minimum = 175 - 20 = 155

Number of classes = 8

so,

Class width = 155 / 8 = 19.375

∴ the class limits will be

20   - 39

40   - 59

60   - 79

80   - 99

100  - 119

120  - 139

140  - 159

160  - 179

Low class boundary = Lower class limit - 0.5

Upper class boundary = upper class limit + 0.5

so

Class Boundaries are;

19.5 - 39.5, 39.5 - 59.5, 59.5 - 79.5, 79.5 - 99.5, 99.5 - 119.5, 119.5 - 139.5, 139.5 - 159.5, 159.5 - 179.5.

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.