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What is the arc measure, in degrees, of major arc \stackrel{\large{\frown}}{ADC} ADC ⌢ A, D, C, start superscript, \frown, end superscript on circle PPP below?

Sagot :

MrRoyal

Answer:

[tex]\stackrel{\large{\frown}}{ADC} = 186^{\circ}[/tex]

Step-by-step explanation:

Given

See attachment

Required

Determine the measure of [tex]\stackrel{\large{\frown}}{ADC}[/tex]

[tex]The\ sum\ of\ angles\ in\ a\ circle\ is[/tex] [tex]360^{\circ}[/tex].

So, we have:

[tex]\stackrel{\large{\frown}}{ADC} + \stackrel{\large{\frown}}{APB} + \stackrel{\large{\frown}}{BPC} = 360^{\circ}[/tex]

Where:

[tex]\stackrel{\large{\frown}}{APB} = 70^{\circ}[/tex]

[tex]\stackrel{\large{\frown}}{BPC} = 104^{\circ}[/tex]

Substitute these values in the above equation.

[tex]\stackrel{\large{\frown}}{ADC} + 70^{\circ} +104^{\circ} = 360^{\circ}[/tex]

[tex]\stackrel{\large{\frown}}{ADC} + 174^{\circ} = 360^{\circ}[/tex]

Collect Like Terms:

[tex]\stackrel{\large{\frown}}{ADC} = 360^{\circ} - 174^{\circ}[/tex]

[tex]\stackrel{\large{\frown}}{ADC} = 186^{\circ}[/tex]

View image MrRoyal
moistscissors

Answer:

186 is correct on khan academn=y

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