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Use the half reaction method to balance the following reaction in acid:

I2 + Na2S2O3 -> Na2S2O4 + NaI
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Sagot :

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Answer:

I2 + 2S2O3^2- --------> S4O6^2- + 2I^-

Explanation:

The correct equation is;

2Na2S2O3 + I2 → Na2S4O6 + 2NaI

Oxidation half equation;

2S2O3^2- --------> S4O6^2- + 2e-

Reduction half equation;

I2 + 2e ----------> 2I^-

Overall balanced redox reaction equation;

I2 + 2S2O3^2- --------> S4O6^2- + 2I^-

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