PhantomPac
Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

The picture is sideways. Please help, much appreciated! BRAINLIEST WILL BE GIVEN FOR THE HELP (SHOW WORK).​

The Picture Is Sideways Please Help Much Appreciated BRAINLIEST WILL BE GIVEN FOR THE HELP SHOW WORK class=

Sagot :

mhanifa

Answer:

  • 14 m

Step-by-step explanation:

Let the shorter side be x

Then the longer side is x + 1

Perimeter is:

  • P = 2( x + x + 1) = 2(2x + 1) = 4x + 2

The value of perimeter is at most 60 meters. P ≤ 60.

Solve the inequality:

  • 4x + 2 ≤ 60
  • 4x ≤ 58
  • x ≤ 58/4
  • x ≤ 14.5

Since x is the integer, its greatest value is 14 m

XxTheLegendxX

[tex]{ \large{ \red{➾ \: \: \underline {\bf{ \underline{Let \: \: the \: \: width \: \: of \: \: rectangle \: \: be \: \: y}}}}}}[/tex]

[tex]{ \large{ \blue{➾ \: \: \underline {\bf{ \underline{Then \: \: the \: \: length \: \: of \: \: rectangle \: \: be \: \: (y + 1)}}}}}}[/tex]

[tex]{ \large{ \green{✪ \: \: \boxed{ \boxed{ \rm{Perimeter \: \: of \: \: rectangle = 2 \times (length + breadth)}}}}}}[/tex]

[tex]{ \large{ \pink{⇛ \: \: \sf{Perimeter = 2 \times (y + y + 1)}}}}[/tex]

[tex]{ \large{ \orange{⇛ \: \: \sf{Perimeter = 4y + 2}}}}[/tex]

[tex]{ \large{ \purple{ ✒ \: \: \: \tt{Here \: \: given = \: Perimeter \: \: is \: \: at \: \: most \: \: 60 \: m}}}}[/tex]

[tex]{ \large{ \red{ ⇝ \: \bf{So \: \: perimeter \leqslant 60}}}}[/tex]

[tex]{ \large{ \green{ \underline{ \rm{Now \: \: we \: \: have \: \: to \: \: solve \: \: inequality}} \colon}}}[/tex]

[tex]{ \large{ \blue{➠ \: \: \bf{4y + 2 \leqslant 60}}}}[/tex]

[tex]{ \large{ \orange{➠ \: \: \bf{4y \leqslant 58}}}}[/tex]

[tex]{ \large{ \purple{➠ \: \: \bf{y \leqslant { \cancel\dfrac{58} {4 }^ { \: \: {14.5}} {}} }}}}[/tex]

[tex]{ { \blue{➠ \: \: \bf{y(Width \: \: of \: \: rectangle ) \: \: \leqslant 14.5 \: \: \: { \underline{ \underline{(But \: \: y \: \: is \: \: an \: \: integer)}}}}}}} [/tex]

[tex]{ \large{ \rm{ \green{ ∴ \: \: \: \: { \boxed{ \boxed{\bf{y \: (Width \: \: of \: \: rectangle ) \: \: greatest \: \: value \: = 14 \: \: m \: \: \:{ \underline{ \underline{}}}}}}} }}} \: \: { \large{ \green{ \rm{Ans.}}}}}[/tex]

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.