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Peter is renting two kinds of rafts for a vacation company. One type seats 3
people and the other seats 5 people. If 53 people are using the vacation
company and he rents 13 rafts, how many of each type of raft does he rent?

Sagot :

LanceLongFei

Answer:

Peter rents 6 of the rafts seating 3 people, and 7 of the rafts seating 5 people.

Step-by-step explanation:

Let [tex]x[/tex] denote the number of rafts seating 3 people and [tex]y[/tex] the number of rafts seating 5 people. The total number of rafts is 13, so [tex]x+y=13[/tex]. We can also assume that every raft is filled to the brim (it isn't stated explicitly though, but it's probably the intention of the question maker), so [tex]3x+5y=53[/tex].

It's always a good idea to put these equations under each other:

[tex]\left \{ {{x+y = 13} \atop {3x+5y=53}} \right.[/tex]

We can subtract the first equation three times from the second one to obtain [tex](3x+5y)-3(x+y) = 53 - 3(13)\\3x-3x + 5y - 3y = 53 - 39\\2y = 14\\y=\frac{14}{2} = 7[/tex]

Now, substitute this found value for [tex]y[/tex] into [tex]x+y = 13[/tex] and we see that [tex]x=6[/tex]. We are now done: Peter rents 6 of the rafts seating 3 people, and 7 of the rafts seating 5 people.

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