gangelucci17
Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

If the spring constant is 12.6N/m and a spring is stretched by 0.25m, how much force has been applied?

Sagot :

Answer:

3.15N

Explanation:

We use this equation:

F= k∆x

Where ∆x refers to the amount or stretch or compression and k is the spring constant.

F = force

k = spring constant

∆x = change in length of spring

To find the value of F:

F= k∆x

F= 12.6x0.25

F= 3.15N

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.