yeeet45
Answered

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iii) Find the values of x
when y = 1

Sagot :

If x = 3 and y = - 1 , find the values of the following using in identity: (9y^2 - 4x^2)(81y^4 + 36x^2y^2 + 16x^4)
Answer · 1 vote
Formula, a^3 - b^3 = (a - b)(a^2 + ab + b^2) a^3 + b^3
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