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If f(1) = 2 and f(n+1) = f(n)^2 – 3 then find the value of f(3).

Sagot :

Answer:

The value of f(3) = -2.

Step-by-step explanation:

First of all, let's find f(2).

[tex]f(n+1)=f(n)^{2}-3[/tex]

[tex]f(1+1)=f(1)^{2}-3[/tex]

[tex]f(2)=f(1)^{2}-3=2^{2}-3=1[/tex]

Now, we can find f(3):

[tex]f(2+1)=f(2)^{2}-3[/tex]

[tex]f(3)=f(2)^{2}-3=1^{2}-3=-2[/tex]

Therefore, the value of f(3) = -2.

I hope it helps you!