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Sagot :
Answer:
The equation of the straight line is 4x +y = 1
Step-by-step explanation:
Step(i):-
Given points are (-1,5) and ( 2,-7)
Slope of the line
[tex]m =\frac{y_{2}-y_{1} }{x_{2} -x_{1} } =\frac{-7-5}{2-(-1)} = \frac{-12}{3} = -4[/tex]
slope of the line m = -4
Step(ii):-
The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4
[tex]y - y_{1} = m( x-x_{1} )[/tex]
y - 5 = -4 ( x-(-1))
y -5 = -4 x -4
4 x + y -5 +4=0
4x +y -1 =0
Final answer:-
The equation of the straight line is 4x +y = 1
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