gabbycooper224
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A positive charge of 5.0×10−5 C is 0.040 m from a second positive charge of 2.0×10−6
Calculate the force between the charges.
A) 1.4×10−2 N

B) 5.6×102 N

C) 2.3×101 N

D)5.6×10−2 N

Sagot :

messiah13carmelo
B cause I took the test
Lanuel

The force between the charges is equal to: B. [tex]5.6 \times 10^2\;N[/tex]

Given the following data:

  • Charge 1 = [tex]5.0\times 10^{-5}\; C[/tex]
  • Charge 2 = [tex]2.0\times 10^{-6}\; C[/tex]
  • Distance = 0.040 meter.

Scientific data:

  • Coulomb's constant = [tex]8.988\times 10^9 \;Nm^2/C^2[/tex]

To calculate the force between the charges:

How to calculate electrostatic force.

Mathematically, the electrostatic force between two (2) charges is given by this formula:

[tex]F = k\frac{q_1q_2}{r^2}[/tex]

Where:

  • q represent the charge.
  • r is the distance between two charges.
  • k is Coulomb's constant.

Substituting the given parameters into the formula, we have;

[tex]F = 8.988\times 10^9 \times \frac{5.0\times 10^{-5}\times 2.0\times 10^{-6}}{0.040^2}\\\\F = \frac {8.988\times 10^9 \times 1.0\times 10^{-5}}{0.0016}\\\\F = \frac {0.8988}{0.0016}\\\\F = 5.6 \times 10^2\;N[/tex]

Read more on charges here: brainly.com/question/4313738

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