likesomenewromantic
Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

115 mL of a 2.35 M potassium
fluoride (KF) solution is diluted with 1.28 L of water. What is the new concentration in molarity?
? M KF

Sagot :

ardni313

The new concentration : = 0.194 M

Further explanation

Given

115 mL(0.115 L) of a 2.35 M Potassium  fluoride (KF)

1.28 L of water

Required

The new concentration

Solution

Dilution is the process of adding solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂  

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = volume of the solution after dilution

V₂=0.115 + 1.28 = 1.395 L

Input the value :

M₂ = (M₁V₁)/V₂

M₂ = (2.35 x 0.115)/1.395

M₂ = 0.194

Answer: 0.194

Explanation:

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.