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Magnesium reacts with iron chloride solution. Calculate the mass of iron produced in mg

Magnesium Reacts With Iron Chloride Solution Calculate The Mass Of Iron Produced In Mg class=

Sagot :

Answer: 0.000187 mg of iron is produced.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} Mg=\frac{0.120g}{24g/mol}=0.005moles[/tex]  

[tex]3Mg+2FeCl_2\rightarrow 2Fe+3MgCl_2[/tex]

As [tex]FeCl_2[/tex] is the excess reagent,  [tex]Mg[/tex] is the limiting reagent.

According to stoichiometry :  

3 moles of [tex]Mg[/tex] give = 2 moles of [tex]Fe[/tex]

Thus 0.005 moles of [tex]Mg[/tex] give =[tex]\frac{2}{3}\times 0.005=0.0033moles[/tex]  of [tex]Fe[/tex]

Mass of [tex]Fe=moles\times {\text {Molar mass}}=0.0033moles\times 56g/mol=0.187g=0.000187mg[/tex]       (1g=1000mg)

Thus 0.000187 mg of iron is produced.

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