Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Answer: The population in 2025 will be 7669
Step-by-step explanation:
a) When we have an initial quantity A, and we have an increase of the X%, the new quantity is written as:
new quantity = A + A*(X%/100%) = A*(1 + X%/100%)
In this case, our initial quantity is 3500, the town's population in 2005.
And X% = 4%.
We know that each year, the population increases by 4%.
Then if P(1) is the population one year after 2005, this is:
P(1) = 3500*(1 + 4%/100%) = 3500*(1.04)
After another year, the population increases again:
P(2) = (3500*(1.04))*(1 + 4%/100%)) = 3500*(1.04)*(1.04) = 3500*(1.04)^2
Well, we already can see the pattern here, the population N years after 2005 will be:
P(N) = 3500*(1.04)^N
b) Now we want to know the population in 2025.
N represents the number of years after 2005, then we will have:
N = 2025 - 2005 = 20
2025 is 20 years after 2005.
Then the population in 2025 will be:
P(20) = 3500*(1.04)^20 = 7,668.9
And we can not have a 0.9 of a person, so we should round it up to the next whole number, then the population in 2025 will be 7669
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.