Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
[tex]\mathbf{Here \ is \ the \ missing \ part \ of \ the \ question} \\ \\ \mathbf{The \ genome \ of \ Escherichia \ coli \ consists \ of \ 4380 \ genes, \ encoding \ 4290} \\ \\ \mathbf{ proteins, \ in \ jus t \ 5175720 \ base \ pairs. \ What \ percent \ fraction \ of\ the} \\ \\ \mathbf{ Escherichia \ coli \ genes \ encode \ proteins?}[/tex]
Answer:
1182
Explanation:
From the information given:
Number of present genes = 4380
the total no. of protein-encoding = 4290
Total no. of base pairs = 5175720
The percentage fraction of genes encoding the protein is;
total no of protein-encoding gene/total no of present genes
[tex]\mathbf{\dfrac{4290}{4380} = 0.9795}[/tex]
= 97.95%
The average number of base pairs per protein-coding gene is;
= total no. of base-pair/ no of present genes
[tex]\mathbf{ \dfrac{5175720}{4380} = 1181.6} \\ \\ \simeq \mathbf{1182}[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.