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In the reaction Cu(s) + 2 AgNO3(aq) -> 2 Ag(s) + Cu(NO3)2(aq) how much Ag can be produced from 49.1 g of copper

Sagot :

ihlester

Answer:167.9 g Ag

Explanation: 1 mol Cu + 2 mol AgNO3 = 2 mol Ag + 1 mol Cu(NO3)2

63.55 g Cu —> 2*107.688 g Ag

So 49.1 g Cu —> (49.1/63.55)*2*107.688 = 167.9 g Ag

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