Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A farming community begins with one resident. Then every year, the number of residents multiplies by 10 Write an expression using an exponent to

represent the number of residents in the community after 5 years


Sagot :

Answer:

After 10 years , the number of residents in the community = 100,007.45

Step-by-step explanation:

Let P be the population of a farming community.

As we know that,

Exponential Growth model is :

P(t) = P₀[tex]e^{kt}[/tex]      ........(1)

where P₀ is the initial state , k is the growth constant.

As given,

A farming community begins with one resident.

⇒At t = 0 , P(t) = 1

∴ Put t = 0 in equation (1), we get

1 = P₀[tex]e^{0}[/tex]

⇒1 = P₀

∴  equation (1) becomes

P(t) = [tex]e^{kt}[/tex]    ......(2)

As given, every year, the number of residents multiplies by 10

⇒At t = 1 , P(t) = 10

∴ Put t = 1 in equation (2), we get

10 = [tex]e^{k}[/tex]

Taking ln both side we get

ln(10) = ln([tex]e^{k}[/tex] )

⇒2.3026 = k

∴  equation (2) becomes

P(t) = [tex]e^{2.3026t }[/tex]

Now, we have to find the population at t = 5

⇒P(5) = [tex]e^{5(2.3026} = e^{11.513} = 100,007.45[/tex]

So, we get

After 10 years , the number of residents in the community = 100,007.45

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.