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Write an equation that is perpendicular to the line y = 5x - 1 and passes through the point (10, 8)

Sagot :

abidemiokin

Answer:

y = -1/5 x + 10

Step-by-step explanation:

The equation of a line in point slope form is expressed as;

y - y0 = m(x-x0)

m is the slope

(x0, y0) is the point on the line

Given the equation y = 5x -1

Slope m = 5

Slope of the line perpendicular to the line will bw M = -1/5

Substitute into the equation

y - 8 = -1/5(x-10)

5(y-8) = -(x-10)

5y - 40 = -x+10

5y = -x+10+40

5y = -x+50

y = -1/5 x + 10

Hence the required equation is y = -1/5 x + 10

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