Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Answer:
0.63 m/s²
Explanation:
Given that
Distance of meteor from earth's surface, r = 2.98R,
where R = radius of the Earth.
The force of the meteor due to the Earth is usually given by
F = GMM(a)/(R + r)² where
F = force exerted
G = gravitational constant
M = Mass of the earth
M(a) = mass of meteor
Remember that F = Ma, so applying that here, we have
acceleration of meteor = GM/(R + r)²
where r = 2.98R so that
acceleration of meteor = GM/(R + 2.98R)²
acceleration of meteor = GM/(3.98R)²
acceleration of meteor = GM / 15.84R²
It should be noted that GM/R² = 10, so
acceleration of meteor = 10/15.84
acceleration of meteor = 0.63 m/s²
Therefore as calculated, the acceleration of the meteor is 0.63 m/s²
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.
