Answered

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An object completes 10 cycles in 50s.
a. What is the period of its rotation?
b. What is the frequency of its rotation?

Sagot :

alonsojair441

Answer:

.

Explanation:

quasarJose

Explanation:

Given parameters:

Number of cycles  = 10cycles

Time taken  = 50s

Unknown:

Period of its rotation  = ?

Frequency of its rotation  = ?

Solution:

The period of rotation is the time taken time taken for a body to complete a number of rotation;

 Period  = [tex]\frac{t}{n}[/tex]  

t is the time

n is the number of cycles

 Period  = [tex]\frac{50}{10}[/tex]  = 5s

The period is 5s

Now, frequency is the inverse of period;

   F = [tex]\frac{1}{period}[/tex]  = [tex]\frac{1}{5}[/tex]   = 0.2Hz

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