Answered

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what are the roots of the equation -3x + 19 = -x^2+1​

Sagot :

mhanifa

Answer:

  • (3 ± 3√7i)/2

Step-by-step explanation:

  • -3x + 19 = -x^2+1​
  • x^2 - 3x + 19 - 1 = 0
  • x^2 - 3x + 18 = 0
  • x = (3 ± √9 - 72)/2
  • x = (3 ± √-63)/2
  • x = (3 ± 3√7i)/2

It has no real solutions and two complex roots

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