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Sagot :
Answer:
The relative velocity of the motorcycle to a passenger in the car is 30 km/h
Explanation:
The question relates to the principle of relative velocity and reference frames
The given parameters are;
The velocity of the motorcycle, v₁ = 120 km/h
The velocity of the car, v₂ = 90 km/h
The relative velocity of an object X with regards to another object Y is the velocity the object X will seem to be moving with to an observer in the rest frame of object Y written as [tex]\underset{v}{\rightarrow}_{X|Y}[/tex] = [tex]\underset{v}{\rightarrow}_{X}[/tex] - [tex]\underset{v}{\rightarrow}_{Y}[/tex]
Therefore, the relative velocity of the motorcycle to the car is [tex]v_{1|2}[/tex] = v₁ - v₂, which give;
[tex]v_{1|2}[/tex] = 120 km/h - 90 km/h = 30 km/h
The relative velocity of the motorcycle to a passenger in the car = 30 km/h.
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