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Sagot :
Answer:
435,307
Step-by-step explanation:
Given that :
p = 0.18
Zcritical = 99%
Error (E) = 1.5% = 1.5/100 = 0.0015
Sample size (n) can be obtained using the relation :
n = (Zcrit / E)^2 * (p * q)
q = 1 - p ; q = 1 - 0.18 = 0.82
Zcrit at 99% equals 2.576
n = (2.576 / 0.0015)^2 * (0.18 * 0.82)
n = (1717.3333)^2 * (0.1476)
n = 2949233.66328889 * 0.1476
n = 435306.888701440164
n = 435,307 samples
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