Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

dont do question A
plzzzzzzzzzzzzzzzzzz

Dont Do Question A Plzzzzzzzzzzzzzzzzzz class=

Sagot :

absor201

Answer:

a) Factors of [tex]x^2-2x=x(x-2)[/tex]

b) Factors of [tex]6x^2+12x=6x(x+2)[/tex]

c) Factors of [tex]3x^3-9x=3x(x^2-3)[/tex]

d) Factors of [tex]4x^2+28x^3=4x^2(1-7x)[/tex]

Step-by-step explanation:

We need to factorise

a) [tex]x^2-2x[/tex]

Taking x common:

[tex]x^2-2x\\=x(x-2)[/tex]

So factors of [tex]x^2-2x=x(x-2)[/tex]

b) [tex]6x^2+12x[/tex]

Taking 6x common:

[tex]6x^2+12x\\=6x(x+2)[/tex]

So factors of [tex]6x^2+12x=6x(x+2)[/tex]

c) [tex]3x^3-9x[/tex]

Taking 3x common:

[tex]3x^3-9x\\=3x(x^2-3)[/tex]

So factors of [tex]3x^3-9x=3x(x^2-3)[/tex]

d) [tex]4x^2+28x^3[/tex]

Taking 4x common

[tex]4x^2+28x^3\\=4x^2(1+7x)[/tex]

So factors of [tex]4x^2+28x^3=4x^2(1-7x)[/tex]

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.