Answer:
The perimeter of square will be 18 units
Step-by-step explanation:
We are given that the coordinates of three vertices of a square A (-2 1/2 , 1 1/2), B (-2 1/2 -3), and C (2,1 1/2 )
When point D is placed on this perimeter.
We have to find the perimeter of the square.
First we have to find the side of square by using the distance formula
Distance formula
[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Coordinates of A=(-5/2,3/2)
Coordinates of B=(-5/2,-3)
Length of side AB=[tex]\sqrt{(-5/2+5/2)^2+(-3-3/2)^2}[/tex]
Length of side AB=[tex]\sqrt{0+(-9/2)^2}[/tex]
Length of side AB=9/2 units
Now, the perimeter of square=4 (side)
Using the formula
Perimeter of square=4(9/2)=18 units
