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Write an equation in slope intercept form of the line that passes through (-2,10) and (1,1).

Sagot :

sunitadangol1234

Answer:

(-2,10)=x1,y1

(1,1)=x2,y2

we have,

(y-y1)=(y2-y1)/(x2,x1)[(x-x1)]

(y-10)=(1-10)/(1+2)[x+2]

y-10=-9/3(x+2)

y-10=-3(x+2)

y-10=3x+6

y=3x+16

unicorn3125

Answer:

        y = -3x + 4

Step-by-step explanation:

The slope of a line passing through two points: (x₂, y₂) and (x₁, y₁) is:

                                                                               [tex]\bold{m=\dfrac{y_2-y_1}{x_2-x_1}}[/tex]

(-2, 10)  ⇒  x₁ = -2,  y₁ = 10

(1, 1)    ⇒  x₂ = 1,  y₂ = 1

So:

      [tex]\bold{m=\dfrac{1-10}{1+2}=\dfrac{-9}{3}=-3}[/tex]

The point-slope form of equation of line is y - y₀ = m(x - x₀)

We can pick any of given poins, so:

x₀ = 1,  y₀ = 1   and  m = -3

y - 1 = -3(x - 1)

y = -3x + 3 + 1

y = -3x + 4      ←  slope intercept form of the line

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