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20 POINTS

An object released from rest at time t = 0 slides down a frictionless
incline a distance of 2 m during the time interval from t=0 s to t = 1 s.
The distance traveled by the object during the time interval from t = 2s
to t = 3s is: (A) 15 m (B) 10 m (C) 5 m (D) 2 m (E) 1m

Sagot :

Answer:

c

Explanation:

NusrathC

Answer:

10m

Explanation:

let's take the acceleration as a constant throughout the complete motion...

therefore first let's find the acceleration

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ 2 = \frac{1}{2} a {1}^{2} \\ a = 4m {s}^{ - 2} [/tex]

then we have to find v1

apply V = u + at

v = 4×1

= 4ms^-1

lets find the distance travel by the object DURING THE TIME INTERVAL 1-2

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = 4 \times 1 + \frac{1}{2} \times 4 \times {1}^{2} \\ s= 6m [/tex]

then let's find the V2

[tex] {v}^{2} = {u}^{2} + 2as \\ {v}^{2} = {4 }^{2} + 2 \times 4 \times 6 \\ {v}^{2} = 64 \\ v = \sqrt{64} = 8m {s}^{ - 1} [/tex]

then let's find the distance travel by the object during time interval 2s to 3s

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = 8 \times 1 + \frac{1}{2} \times 4 \times {1}^{2} \\ s = 10m [/tex]

View image NusrathC
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