Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Answer: 0.2417
Step-by-step explanation:
- 10! / (10-5)!5! x 0.53^5 x 0).47^5
To solve the problem we must know Binomial distribution.
The probability that exactly half have some college education is 17.3425%.
Given to us
- The probability of a person having at least some college education = 63% = 0.63
To solve the problem we will use the Binomial distribution, therefore,
- The probability of a person having at least some college education, p = 63% = 0.63
- The probability of a person not having at least some college education, q = 37% = 0.37
- Number of people selected for college education (Sample Size) = 10
Using the formula for Binomial Distribution,
We want the probability that exactly half have some college education, therefore, x = 5
[tex]P(x) = ^nC_x\ p^x\ q^{(n-x)}[/tex]
Substitute the values we get,
[tex]P(5) = ^{10}C_5\ (0.63)^{5}\ (0.37)^{(10-5)}\\\\P(5) = ^{10}C_5\ (0.63)^{5}\ (0.37)^{5}\\\\P(5) = 0.173425 = 17.3425\%[/tex]
Hence, the probability that exactly half have some college education is 17.3425%.
Learn more about Binomial distribution:
https://brainly.com/question/12734585
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
