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A 1000 kg car moving at 108 km/h jams on its brakes and comes to a stop. How much work was done by friction?

Sagot :

Answer:

The work done by friction was [tex]-4.5\times10^{5}\ J[/tex]

Explanation:

Given that,

Mass of car = 1000 kg

Initial speed of car =108 km/h =30 m/s

When the car is stop by brakes.

Then, final speed of car will be zero.

We need to calculate the work done by friction

Using formula of work done

[tex]W=\Delta KE[/tex]

[tex]W=K.E_{f}-K.E_{i}[/tex]

[tex]W=\dfrac{1}{2}mv_{f}^2-\dfrac{1}{2}mv_{f}^2[/tex]

Put the value of m and v

[tex]W=0-\dfrac{1}{2}\times1000\times(30)^2[/tex]

[tex]W=-450000 \ J[/tex]

[tex]W=-4.5\times10^{5}\ J[/tex]

Hence, The work done by friction was [tex]-4.5\times10^{5}\ J[/tex]

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