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If Sin theta=3/4,find the value of cos theta

Sagot :

onyebuchinnaji

Answer:

[tex]Cos \ \theta = \frac{\sqrt{7} }{4}[/tex]

Step-by-step explanation:

Given;

Sin θ = 3/4

To calculated Cos θ;

make a sketch of right-angled triangle with following sides;

opposite side = 3

hypotenuse side = 4

then, the adjacent  side will be calculated from Pythagoras theorem;

let the adjacent side = b

b² = 4² - 3²

b² = 16 - 9

b² = 7

b = √7

Therefore, Cos θ is now calculated as;

Cos θ = adjacent / hypotenuse

Cos θ = √7/4

[tex]Cos \ \theta = \frac{\sqrt{7} }{4}[/tex]

Therefore, [tex]Cos \ \theta = \frac{\sqrt{7} }{4}[/tex]

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