Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A2. Find y' and y" for y^2 = x^2
+ sinxy

Sagot :

Answer:

y'   = (2x + y cosxy)/(2y + x cosxy)

Step-by-step explanation:

Using implicit differentiation:

y^2 = x^2 + sin xy

2y y' = 2x + cos xy  * (xy' + y)

2y y' = 2x + xy' cos xy + y cos xy

2y y' - xy' cosxy = 2x + ycos xy

y'   = (2x + y cosxy)/(2y - x cosxy)

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.