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Sagot :
Answer:
The kinetic energy of the boy is 20 times that of the kinetic energy of the girl.
Explanation:
It is given that,
The mass of the boy is 20 times that of girl.
Let [tex]m_b[/tex] and [tex]m_g[/tex] are the mases of boy and the girls.
A boy and girl are running with the same speed.
The formula for the kinetic energy is given by :
[tex]E=\dfrac{1}{2}mv^2[/tex]
Where m is mass and v is speed
As speed is same for both boy and girl.
Kinetic energy of a girl,
[tex]K_g=\dfrac{1}{2}m_gv^2[/tex] ...(1)
As [tex]m_b=20m_g[/tex]
Kinetic energy of a boy,
[tex]K_b=\dfrac{1}{2}m_bv^2\\\\=\dfrac{1}{2}\times 20m_g\times v^2\ ....(2)[/tex]
From equation (1) and (2) :
[tex]\dfrac{K_g}{K_b}=\dfrac{\dfrac{1}{2}m_gv^2}{\dfrac{1}{2}m_bv^2}\\\\=\dfrac{\dfrac{1}{2}m_gv^2}{\dfrac{1}{2}\times 20 m_gv^2}\\\\\dfrac{K_g}{K_b}=\dfrac{1}{20}\\\\K_b=20K_g[/tex]
So, the kinetic energy of the boy is 20 times that of the kinetic energy of the girl. Hence, this is the required solution.
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