Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:
It will not hit.
Explanation:
In this problem, we need to tell that was the cannonball able to hit its target of 50 meters when the initial velocity was 20 m/s.
When it will hit the target, final velocity, v = 0
Using third equation of motion as follows :
[tex]v^2-u^2=2as[/tex]
Here, a =-g
[tex]s=\dfrac{u^2}{2g}\\\\s=\dfrac{(20)^2}{2\times 9.8}\\\\=20.40\ m[/tex]
The target is in a straight line 50m away on the x-axis. As 50m is far from 20.40 m and that’s why it won’t hit.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
