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Sagot :
Answer:
[tex]\frac{3\sqrt{2} }{2}[/tex]
Step-by-step explanation:
Given
[tex]\frac{\sqrt{2} }{2}[/tex] + [tex]\frac{2}{\sqrt{2} }[/tex] ← rationalise the denominator by multiplying by [tex]\frac{\sqrt{2} }{\sqrt{2} }[/tex]
= [tex]\frac{\sqrt{2} }{2}[/tex] + ( [tex]\frac{2}{\sqrt{2} }[/tex] × [tex]\frac{\sqrt{2} }{\sqrt{2} }[/tex] )
= [tex]\frac{\sqrt{2} }{2}[/tex] + [tex]\frac{2\sqrt{2} }{2}[/tex]
= [tex]\frac{3\sqrt{2} }{2}[/tex]
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