Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Let [tex]j[/tex] be the number of pages Janet has to read.
so Hallie has [tex]10j[/tex] pages to read.
Altogether, they must read [tex]10j + j[/tex] pages, which is [tex]11j[/tex]. So this means that [tex]11j[/tex] must be equal to [tex]264[/tex].
If you divide both bits by [tex]11[/tex], you get [tex]j = \frac{264}{11} = 24[/tex].
So, Janet has to read [tex]j[/tex] pages, which is [tex]24[/tex], and Hallie has to read [tex]10j[/tex] pages, which is [tex]240[/tex].
so Hallie has [tex]10j[/tex] pages to read.
Altogether, they must read [tex]10j + j[/tex] pages, which is [tex]11j[/tex]. So this means that [tex]11j[/tex] must be equal to [tex]264[/tex].
If you divide both bits by [tex]11[/tex], you get [tex]j = \frac{264}{11} = 24[/tex].
So, Janet has to read [tex]j[/tex] pages, which is [tex]24[/tex], and Hallie has to read [tex]10j[/tex] pages, which is [tex]240[/tex].
they read all together you divide then the quotient you divide it by 10 that's how u get ur answer13.2
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
