Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

C(squared)L(squared) + 100v(squared) = 100c(squared)
I have to solve for L

Sagot :

first subtract 100v² from both sides to get:

C²L²=100c²-100v²

Then divide both sides by C²:

L²=(100c²-100v²)/C²

Then take the square root of both sides:

L=+ or - the square root of (100c²-100v²)/C²
GrandNecro

Answer:

L = ±√( (100c² - 100v²) / C² )

Step-by-step explanation:

You're just doing reverse PEMDAS.

So first get all the values correlated with L on one side and the non-L values on the other side using subtraction/addition.

Then remove all coefficient using multiplication/division.

Then take the sqareroot to get rid of the squre on the v.

Remember that taking squareroot gives a ± answer because

(x)² = (-x)²

View image GrandNecro
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.