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The sum of 3 sixteens and 2 nines

Sagot :

[tex] \frac{3}{16} + \frac{2}{9} [/tex]

find a common factor that can make the denominators (bottom number) the same number. In this case, that number is 144 (denominators multiplied (9 x 16) ) 
Multiple each side to get the denominator to equal 144.

[tex] \frac{3}{16} \frac{(9)}{(9)} = \frac{27}{144} \\ \\ \frac{2}{9} \frac{(16)}{(16)} = \frac{32}{144} [/tex]

[tex] \frac{27}{144} + \frac{32}{144} = \frac{59}{144} [/tex]

The sum is  [tex] \frac{59}{144} [/tex]


answer=66

3x16=48

9x2=18

48+18=66