Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

what are the real zeros for the function
f(x)=x^2-3x-28

Sagot :

Factor the equation: (x-7)(x+4) Solve for X: X-7=0 x+4=0 X=7 x=-4 A zero is when the function crosses the x-axis which is solved by setting the function equal to zero.
konrad509
[tex]x^2-3x-28=0\\ x^2-7x+4x-28=0\\ x(x-7)+4(x-7)=0\\ (x+4)(x-7)=0\\ x=-4 \vee x=7[/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.