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Sagot :
okay, so what this means is that the larger number is
10 + 2x
and the smaller number is x
put them together and set them equal to forty.
10+3x=40
subtract ten from both sides.
3x=30
devide both sides by three
x=10
now you have the smaller number, so plug it back in to the equation we said was the bigger number.
10+2(10)
The larger number is 30.
10 + 2x
and the smaller number is x
put them together and set them equal to forty.
10+3x=40
subtract ten from both sides.
3x=30
devide both sides by three
x=10
now you have the smaller number, so plug it back in to the equation we said was the bigger number.
10+2(10)
The larger number is 30.
first lets represent
x will be the smaller number
while the larger one is 2x+10
so their sum is 40
so x+2x+10=40
3x+10=40
3x=30
x=10
so the smaller one is 10 while the larger is
2x+10
2(10)+10
20+10
=30
hope this answeres you problem :)
x will be the smaller number
while the larger one is 2x+10
so their sum is 40
so x+2x+10=40
3x+10=40
3x=30
x=10
so the smaller one is 10 while the larger is
2x+10
2(10)+10
20+10
=30
hope this answeres you problem :)
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