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Find the values of l and m that make each equation true

(7+m)+(4l-10)i=3 - 6i

Sagot :

crisforp
7 + m = 3 and 4 * l - 10 =  - 6;
=> m = 7 - 3 => m = 4;
4 * l = 10 - 6 => 4 * l = 4 => l = 4 / 4 => l = 1.

the values of l and m that make each equation true are

m=-4  and l = 1

Given :

the given equation is [tex](7+m)+(4l-10)i=3 - 6i[/tex]

The given equations is in the form of a+ib where 'a' is the real part and 'b' is the imaginary part

Equate the real part and solve for m

[tex](7+m)+(4l-10)i=3 - 6i\\7+m=3\\m=3-7\\m=-4[/tex]

Now we equate the imaginary part and solve for 'l'

[tex](7+m)+(4l-10)i=3 - 6i\\4l-10=-6\\4l=-6+10\\4l=4\\divide \; by \; 4\\l=1\\[/tex]

So , the value of m=-4  and l=1

Learn more : brainly.com/question/5564133

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