Myres245
Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Each leg of an isosceles triangle is 9 inches
longer than one-half the length of the base. If
the perimeter of the isosceles triangle is
146 inches, what is the length of one leg of the
isosceles triangle?
A 64 in.
B 41 in.
C 50 in.
D 82 in.

Sagot :

ArchimedesEleven
B) 41"
If the legs of 41" are 9" less than half the base, the base is:
(41-9) 2 = 64
All sides of the triangle added together (perimeter):
41" + 41" + 64" = 146"
Hope this helps! ~ArchimedesEleven
rabinshrestha41
let, the base of the given isosceles triangle be "x"
Now,
If the base is x, then the length of the legs will be [tex]9+ \frac{1}{2}x [/tex]
Now, 
Perimeter = sum of all sides
[tex]146 = (9+ \frac{1}{2}x )+(9+ \frac{1}{2}x)+x[/tex]

[tex]146 = 18+x+x[/tex]

[tex]146 - 18 = 2x[/tex]

[tex]128 = 2x[/tex]

[tex] \frac{128}{2} =x[/tex]

[tex]64 =x[/tex]

Now, substitute the value of x in the equation for legs of the triangle,

legs = [tex]9+ \frac{1}{2}x[/tex]
     
       = [tex]9+ \frac{1}{2}(64)[/tex]
   
       = [tex]9+ 32[/tex]
 
       = [tex]41[/tex] inches.

So, the answer to your question is B.


We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.