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Sagot :
let's call the digits a and b, a is ones, b is tens
the number will look something like: aba,aba
the sum of all the digits is 20
a + b + a + a + b + a = 20
4a + 2b = 20
2a + b = 20
b is 5 more than a
b = a + 5
2a + (a + 5) = 20 (because b=a+5)
3a + 5 = 20
3a = 15
a = 5
then go back to one of our equations from before to find b:
a + b + a + a + b + a = 20
5 + b + 5 + 5 + b + 5 = 20
b + b = 0
2b = 0
b = 0
therefore the number is 505,505
the number will look something like: aba,aba
the sum of all the digits is 20
a + b + a + a + b + a = 20
4a + 2b = 20
2a + b = 20
b is 5 more than a
b = a + 5
2a + (a + 5) = 20 (because b=a+5)
3a + 5 = 20
3a = 15
a = 5
then go back to one of our equations from before to find b:
a + b + a + a + b + a = 20
5 + b + 5 + 5 + b + 5 = 20
b + b = 0
2b = 0
b = 0
therefore the number is 505,505
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